2025 · Paper 1

Step 1: Start
Step 2: A=4
Step 3: B=6
Step 4: C=A%B
Step 5: A=C+B
Step 6: B=B-2
Step 7: IF B>=1 THEN GOTO Step 4
Step 8: Output A
Step 9: Stop

Step 1: Start
Step 2: Let the number J be 6 and K be 3
Step 3: Initialize L=2 and M=1
Step 4: L=L*J+K
Step 5: M=M+4
Step 6: If M <= K Then GOTO Step 4 otherwise GOTO Step 7
Step 7: Output L
Step 8: Stop

int y = 2 + 3 * 6 / 2;

int y = 10 % 3 + 7 / 2 + 4 * 3 - 5;

L = (9×5) - (12÷3) × 8^3;

K *= J;

#include<stdio.h>
int main( )
{
  int k=15;
  k++;
  k--;
  printf("%d", ++k);
  return 0;
}

#include<stdio.h>
int main( )
{
  int y = 26;
  y += 4;
  y /= 2;
  printf("%d", y *= 4);
  return 0;
}

#include<stdio.h>
int main( )
{
  int a;
  printf("Enter a number: \t");
  scanf("%d",&a);
  if (a*3 < 9)
    printf("Hello World");
  return 0;
}

#include<stdio.h>
int main( )
{
  int i = 15, j = 8;
  do
  {
    printf("Data Science \n");
  }
  while (i-- > j++);
  return 0;
}

#include<stdio.h>
int main( )
{
  int i = 15, j = 8;
  do
  {
    printf("Data Science \n");
  }
  while (i-- > j++);
  return 0;
}

#include<stdio.h>
int main( )
{
  int p=3;
  do
  {
    printf("%d ", p*=5);
    p=p+7;
  }
  while (p<=20);
  return 0;
}

#include <stdio.h>
int main( )
{
  int a=10, b=7;
  while(a>--b)
  {
    printf("\nKarachi");
    a=a-2;
  }
  return 0;
}

#include <stdio.h>
int main( )
{
  int i;
  for (i=0;i<10;i++)
  {
    printf("%d ",i);
    i++;
  }
  return 0;
}