2023 · Paper 1

Step 1: Start
Step 2: Let the number A be 10 and B be 5
Step 3: Initialize X = 1 and Y = 0
Step 4: X = X * A - B
Step 5: Y = Y + 2
Step 6: If Y <= B Then GOTO Step 4 otherwise GOTO Step 7
Step 7: Output X
Step 8: Stop

Step 1: Start
Step 2: X = 5
Step 3: Y = 4
Step 4: Z = X % Y
Step 5: A = Z + Y
Step 6: Y = Y - 3
Step 7: IF Y >= 1 THEN GOTO Step 4
Step 8: Output A
Step 9: Stop

X = -9;

int y = 2 + 3 * 6 / 2;

int P, Q;
Q = 3 + 4 / 2;

K *= J;

#include <stdio.h>
int main()
{
  int R = 0;
  R++;
  printf("%d", R++);
  return 0;
}

if ((a % 2 == 0) && (a % 3 == 0))

#include <stdio.h>
int main() {
  int n;
  for (n = 10; n > 1 ; n--)
  {
    printf("%d ", n);
  }
  return 0;
}

#include <stdio.h>
int main( )
{
  int a = 10, b = 7;
  while (a > --b)
  {
    printf("\nKarachi");
    a = a - 2;
  }
  return 0;
}

#include <stdio.h>
int main( )
{
  int y = 2;
  while (y == 2)
  {
    y--;
    printf ("%d", y);
  }
  return 0;
}

#include <stdio.h>
int main( )
{
  int y = 2;
  while (y == 2)
  {
    y--;
    printf ("%d", y);
  }
  return 0;
}