2024 · Paper 1

Step 1: Start
Step 2: J = 8
Step 3: K = 3
Step 4: L = J % K
Step 5: M = J / K
Step 6: N = L / M
Step 7: Z = L * M
Step 8: IF Z <= N THEN GOTO Step 4
Step 9: Output Z
Step 10: Stop

A=(9÷5)+(12%3)×8^3

#include <stdio.h>
int main()
{
  int a = 5, b = 10, c = 15;
  a = b * c;
  ++a;
  b = a;
  --b;
  c = b + c - 5;
  printf("a = %d, b = %d, c = %d", a, b, c);
  return 0;
}

c = a && b;

int y=2+3*6/2;

int z = 10 % 4 - 10 / 3 + 8 * 6 + 7

#include<stdio.h>
int main(){
  float side1, side2, side3;
  printf("Enter sides of triangle:");
  scanf("%f%f%f",&side1,&side2,&side3);
  if(side1 == side2 && side2 == side3)
    printf("The Given Triangle is equilateral");
  else if(side1 == side2 || side2 == side3 || side3 == side1)
    printf("The given Triangle is isosceles");
  else
    printf("The given Triangle is scalene");
  return 0;
}

#include<stdio.h>
int main(){
  int a = 12, b = 8;
  do{
    printf("Caterpillar \n");
  }
  while (a-- < b++);
  return 0;
}

#include <stdio.h>
int main()
{
  int k = 1;
  while (++k < 10)
  {
    printf("%d ", k++);
    --k;
  }
  return 0;
}

#include<stdio.h>
int main(){
  int a = 12, b = 8;
  do{
    printf("Caterpillar \n");
  }
  while (a-- < b++);
  return 0;
}

#include <stdio.h>
int main()
{
  int i=1;
  while (i<=5)
  {
    printf("%d ", i*=4);
    i=i+2;
  }
  return 0;
}